This code will not work since it contains an error because curly braces are used in the assignment.
For array assignment you need normal parentheses.

Code:

 
 LOG_FILES=( "/Sandbox/logs/*" )
 for file in ${LOG_FILES[@]}; do
   grep $1 $file
done

However, since "/Sandbox/logs/*" is quoted this results in an array with a single array element "/Sandbox/logs/*".

It works because the array contents gets expanded in the loop, since the variables are used without quotes, but it will not work with files with spaces in the name.

The proper way to do this would be this:

Code:

LOG_FILES=( /Sandbox/logs/* )
for file in "${LOG_FILES[@]}"; do
  grep "$1" "$file"
done

Although if there are not too many files this would be more efficient (and thus faster):

Code:

LOG_FILES=( /Sandbox/logs/* )
grep -h "$1" "${LOG_FILES[@]}"

---

This does not do that . It returns the files that have matches on three lines for ANY of the keywords.

---

You do not need eval here, nor the quotes..

You can just use:

Code:

awk "$RE" filename

Assuming variables A[1-3] contain the strings that we are looking for..