a new file does get created with the line that is not in analysis_log, so it apperas to be working just not sure what the error means (seems like "Medexome\.tar\.bz2" is causing the error message? Thank you very much .
---------- Post updated at 06:58 AM ---------- Previous update was at 06:54 AM ----------
if I remove the \, I get no message... but are they need? Thank you .
So it is "Medexome.tar.bz2"
Hi, cmccabe, yes they are needed. My suggestion was slightly incorrect. Try this instead:
This is a "regex constant" expression..
The double quotes (regex string) would be possible as well, but the dots then would need an extra escape: \. is necessary, since a . would mean "any character" instead of a literal dot. It would probably work too, but theoretically it could mean a false positive...
This User Gave Thanks to Scrutinizer For This Post:
You have two files to compare by searching keyword from one file into another file
File A
23 >pp_ANSWER
24 >aa hello
25 >jau head wear
66 >jss oops
872 >aqq olps ploww oww sss
722 >GG_KILLER
..... large files
File B
Beta done
KILLER
John Mayor
calix meyers
... (5 Replies)
Hi,
I have a file which got only one column and got some keywords. I have another file where the keywords used in the first file are repeated in the second file.
Now I would like to know how many times each keyword from the first file is repeated in the second file.
Request your help on... (1 Reply)
Hi Guys,
I need to read a file until I find a blank line. and in the next iteration I want to continue reading from the line I find a keyword.
For ex: my file looks like
PDS_JOB_ALIAS
CRITERIA_ITEM_TYPE
PDS_JOB_CRITERIA_ITEM
CRITERIA_ITEM_TYPE
First I want to read the file... (2 Replies)
Hi,
In short : I have several log files and I need to find the last file with a certain keyword in it.
# ls -1tr logs
log_hostX.Jan01_0100.gz
log_hostX.Jan01_0105.gz
log_hostX.Jan01_0110.gz
log_hostX.Jan01_0115.gz
log_hostX.Jan01_0120.gz
log_hostX.Jan01_0125.gz
log_hostX.Jan01_0130.gz... (2 Replies)
Hi
I want to implement something like this:
if( keyword1 exists)
then
check if(keyword2 exists in the same line)
then replace keyword 2 with New_Keyword
else
Add New_Keyword at the end of line
end if
eg:
Check for Keyword JUNGLE and add/replace... (7 Replies)
I have input file as below I need to check for a pattern and if it is there in file then I need to print all the lines below BEGIN and END keyword. Could you please help me how to get this in AIX using sed or awk.
Input file:
ABC
******** BEGIN *****
My name is Amit.
I am learning unix.... (8 Replies)
I need to find a file and print its contents
I am trying but it is not working
find -path /opt/app-root/src/.npm/_logs -type f -name "*.log" -print
Version
$ bash -version
GNU bash, version 4.4.12(1)-release (x86_64-pc-msys) (1 Reply)