You need to determine what rounding rules you want to use for tie-breaking cases (see Wikipedia's discussion on rounding)
and you need to realize that even in double precision floating point, the result of a floating point calculation is not always exact (even when computing a value using decimal calculations would be exact). For example, the awk program (which uses double precision floating point for its calculations):
produces the output:
not the output you might expect:
Which shows two examples where decimal arithmetic produces exact results, but binary arithmetic produced one result that was a little bit high and one result that was a little bit low.
Hello again.
I'm trying to use BC to calculate some numbers in a shell script.
I want to have the numbers rounded off to 1 decimal place.
for example:
initsize=1566720
zipsize=4733
I'm trying to get the ratio between them. the equation is:
(($initsize-$zipsize)/$initsize)*100
so... (3 Replies)
Hi,
Can any one help me in finding a solution for rounding off to 2 decimal places.
I am using the following code:
VAR1=.01292105263157894736
VAR2=`echo "scale=2; $VAR1 * 100" | bc -l`
The result I 'm getting is
1.29210526315789473600
But I need the output as 1.29
Thanks
Shash (2 Replies)
Hello,
i have some variables say:
x=1.4
y=3.7
I wish to round off these values to :
x = 2 (after rounding off)
y = 4 (after rounding off)
I am stuck.
Please help. (7 Replies)
Hello,
I searched a lot on this Forum.
Please help me with the below problem.
I want to divide two numbers and the result should be the next nearest whole number.
E.G. Dividing 10.8/5 ideally gives 2.16. But the result should be 3 i.e. rounded off to the next whole number.
Any help will... (2 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (0 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (4 Replies)
Hi,
I am currently using tcsh
I am trying to round a decimal number to the ten-thousandths place
For instance:
1.23456 is rounded up towards 1.2346
I am not looking for truncation, but for rounding. Anyone know how to do this with awk or expr?
Thanks (2 Replies)
Dear Experts,
I'm trying to find a way to round a number but in this way:
14367.577 ---> 14000
I used the following to round the number to the closer integer:
echo $var|awk '{print int($1+0.5)}'
and also:
xargs printf "%1.0f"
However, they don't work for my above... (9 Replies)
Hi all of you,
Would be great if you help me with how to round up to whole number from my input values like
2.99996,2.17890,3.00002,-2.3456,-2.7890
o/p should be like 3,2,3,-2,-3
thnks in adv!!!!
regards (3 Replies)
How to round off a decimal number to higher whole number using ceil command in unix?
Eg. 4.41 or 4.11 or 4.51 should be rounded off to 5. (11 Replies)
Discussion started by: SanjayKumar28
11 Replies
LEARN ABOUT FREEBSD
lrintl
LRINT(3) BSD Library Functions Manual LRINT(3)NAME
llrint, llrintf, llrintl, lrint, lrintf, lrintl -- convert to integer
LIBRARY
Math Library (libm, -lm)
SYNOPSIS
#include <math.h>
long long
llrint(double x);
long long
llrintf(float x);
long long
llrintl(long double x);
long
lrint(double x);
long
lrintf(float x);
long
lrintl(long double x);
DESCRIPTION
The lrint() function returns the integer nearest to its argument x according to the current rounding mode. If the rounded result is too
large to be represented as a long value, an invalid exception is raised and the return value is undefined. Otherwise, if x is not an inte-
ger, lrint() raises an inexact exception. When the rounded result is representable as a long, the expression lrint(x) is equivalent to
(long)rint(x) (although the former may be more efficient).
The llrint(), llrintf(), llrintl(), lrintf(), and lrintl() functions differ from lrint() only in their input and output types.
SEE ALSO lround(3), math(3), rint(3), round(3)STANDARDS
These functions conform to ISO/IEC 9899:1999 (``ISO C99'').
HISTORY
The llrint(), llrintf(), lrint(), and lrintf() routines first appeared in FreeBSD 5.4. The long double variants were introduced in
FreeBSD 8.0.
BSD January 13, 2008 BSD