hi guys.
in bash is there any other way of limiting the time displayed to HH:MM
appart from
(date +"%H:%M") and (date +"%R")?
i want to input time into a database in the form HH:MM
have tried NOW() but this gives me HH:MM:SS
thanks in advance (1 Reply)
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Could anyone suggest me on how to write unix script for displaying yesterdays date ie. if today is 2nd Mar then when i run .sh script i should get displayed as "01-Mar-2010". (5 Replies)
Hi Experts
I'm struggling with the dates in bash scripting.
here is my code
due1=`grep "$member" Due.txt | tail -n 1 | cut -d "," -f2 | tr -d "\15"`
duedate1=`date +%Y-%m-%$due1`
echo $due1
echo $duedate1
if I execute the above code
I get output as
10
2013-09 %10
... (2 Replies)
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
I have a script below and wanted to change the output into three different file format (3 separate script)
#!bin/bash
#input file format postwrf_d01_20131206_0600_f08400.grb2
#postwrf_d01_YYYYMMDD_ZZZZ_f0HHHH.grb2
#zzzz= 0000,0600,1200,1800 (in UTC)
#HHHH=00000,00600,01200,01800 ..ect (in... (1 Reply)
I'm trying to change date format using this script from day/month/year to month/day/year
#!/bin/bash
while read line; do
echo "$line"
date=$(echo "$line" | cut -d/ -f1 )
month=$(echo "$line" | cut -d/ -f2 )
echo $month"/"$date"/2017"
done < ~/Downloads/Dates.csv
But I get output as... (5 Replies)
Discussion started by: sharat
5 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)