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Top Forums UNIX for Dummies Questions & Answers How to pass command line argument in shell script? Post 302848513 by Nsharma3006 on Thursday 29th of August 2013 01:00:48 PM
Old 08-29-2013
How to pass command line argument in shell script?

I need to write a shell script, when I run that script I should pass those arguments if not, then script should not run and pass the error message like
Code:
invalid option - - should pass the argument.

and Exit from the script
 

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script(1)						      General Commands Manual							 script(1)

NAME
script - Makes a transcript of terminal session SYNOPSIS
script [-a] [file] The script command makes a transcript of everything printed on your terminal. OPTIONS
Appends the transcript to file rather than writing it to file. OPERANDS
The name of an output file that will contain the transcript of the session. If this parameter is omitted, the file typescript is written. DESCRIPTION
The transcript is written to file, or appended to file if the -a option is given. If no file name is given, the transcript is saved in the file typescript. The script ends when the forked shell exits. This program is useful when you are using a CRT and want a hard-copy record of the dialog (for example, a technical writer might create an example of a working session this way). If you specify the -a option and the file does not exist, it is created. If you do not specify the -a option and the file exists, it is replaced. RESTRICTIONS
The script command requires a streams based terminal. In single user mode, streams may not be enabled. Under these circumstances, script will exit with no action. If you are the superuser and need to run this command in single user mode, use the following special instruc- tions. Enabling Streams If it is necessary to enable a streams environment in the single user mode, enter the command /sbin/init.d/streams. This command is avail- able to the superuser only. SEE ALSO
Commands: autopush(8), cat(1), echo(1), strsetup(8), tee(1) System Administration script(1)
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