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Top Forums Shell Programming and Scripting Sort, sed, and zero padding date column csv bash scripting Post 302834911 by Don Cragun on Saturday 20th of July 2013 03:08:31 PM
Old 07-20-2013
Quote:
Originally Posted by Yoda
How about using awk and sort?
Code:
awk -F, '
        {
                sub( / .*/, X, $7 )
                split ( $7, V, "/" )
                $7 = sprintf ( "%02d/%02d/%d", V[1], V[2], V[3] )
                print
        }
' OFS=, file | sort -t"," -k 7.9 -k 7.5 -k 7

I'm a little bit confused by this. Yoda's code is usually right on, but the sort keys used here make the last two digits of the year to the end of the line the primary sort key, the last digit of the day to the end of the line the secondary sort key, and the start of the date field to the end of the line the tertiary sort key. (This seems to have worked with the sample data only because the 8th field in all of the input lines was identical and the last digit of the day was a constant on the two input lines with the same year.) I think the sort he intended to perform on the awk output was:
Code:
sort -t"," -k 7.7,7 -k 7.1,7.5

which makes the entire year the primary sort key and the month and day together as the secondary sort key.

With the new requirement to exclude a date range from the output, you could try something like:
Code:
awk -F, -v sd="04/01/2010" -v ed="05/04/2013" '
BEGIN { ss = substr(sd, 7) substr(sd,1,2) substr(sd,4,2)
        es = substr(ed, 7) substr(ed,1,2) substr(ed,4,2)
}
{       sub(/ .*/, X, $7)
        split($7, V, "/")
        cs = sprintf("%d%02d%02d", V[3], V[1], V[2])
        if(cs >= ss && cs <= es) next
        $7 = sprintf("%02d/%02d/%d", V[1], V[2], V[3])
        print
}' OFS=, input.csv | sort -t"," -k 7.7,7 -k 7.1,7.5

If you are using a Solaris/SunOS system, use /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk instead of /usr/bin/awk or /bin/awk.

With the input file:
Code:
1,2,3,4,5,6,4/1/2010 12:00 AM,1
1,2,3,4,5,6,3/11/2010 9:39 AM,2
1,2,3,4,5,6,5/12/2011 3:43 PM,3
1,2,3,4,5,6,12/20/2009 7:23 PM,4
1,2,3,4,5,6,03/02/2009 1:23 AM,5
1,2,3,4,5,6,08/03/2009 2:34 AM,6
1,2,3,4,5,6,04/01/2010 3:45 AM,7
1,2,3,4,5,6,05/01/2013 4:56 AM,8
1,2,3,4,5,6,05/11/2013 12:03 PM,9

the output produced is:
Code:
1,2,3,4,5,6,03/02/2009,5
1,2,3,4,5,6,08/03/2009,6
1,2,3,4,5,6,12/20/2009,4
1,2,3,4,5,6,03/11/2010,2
1,2,3,4,5,6,05/11/2013,9

which drops the lines shown in red in the input because they are in the date exclusion range.
This User Gave Thanks to Don Cragun For This Post:
 

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