I am facing a problem while using the grep command in shell script. Actually I have one file (PCF_STARHUB_20130625_1) which contain below records.
And I have a pattern which is stored in one variable (INPUT_FILE_T), and want to search the pattern from the file (PCF_STARHUB_20130625_1). For that I have used below command
The output of above command is coming as below
Problem is that only one entry is showing in output (It should contain two entries) output should come like below
Is there any technique except grep please tell me.
Please help me on this issue.
Last edited by sumit.vedi1988; 06-25-2013 at 07:11 AM..
Reason: formating
Hello everyone,
I have been trying to get a list of all files containing a line of this type:
};#followed by anything
with any spaces (0 or more or 0 or more tabs) before the } and between each of the characters.
I have been trying this :
grep '*}*;*#*' *.c
but I have not been fully... (1 Reply)
Hi
Is there any way GREP command can return word and not complete line.
My file has following data:
Hello Everyone I am NitinrajSrivastava
Hi Friends Welcome VrajSrivastava
I am using grep 'raj' which is returning me complete line.However I want only the word having keyword 'raj'.
Required... (11 Replies)
Hi
I am facing the below problem.
I have set of lines in which i have to search for only the line which matches with the pattren "/" only.
input:-
/*+ some text */
/*+ some text */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/*... (7 Replies)
Hi,
I am trying to do pattern search using grep command. But i donot know what mistake i'm doing. I am not getting the expected Result. could any one please help me out?
$ cat b.ksh
AasdjfhB
57834B
86234B
472346B
I want to print the line which is starting with either A or 8 and... (10 Replies)
Hello,
I have a bunch of zip files like
SS_SAMPLE_101_123.zip
SS_101_123.zip
SS_SAMPLE_121_345.zip
SS_SAMPLE_222_678.zip
SS_123_890.zip
SS_.zip
The 'ls' should search and list the files such as SS_101_123.zip and SS_123_890.zip alone. Could you please guide me with this.... (5 Replies)
I 'm writing a script to search particular strings from log files. The log file contains lines start with *. The file may contain many other lines start with *. I need to search a particular line from my log file. The grep command is working in command line , but when i run my script, Its printing... (7 Replies)
One more question:
I want to grep "COS_12_TM_4 pattern from a file look likes :
"COS_12_TM_4" " ];I am taking scan_out as the input from the user.
How to search "COS_12_TM_4" in the file which is corresponds to scan_out (12 Replies)
I have this fileA
TEST FILE ABC
this file contains ABC;
TEST FILE DGHT this file contains DGHT;
TEST FILE 123
this file contains ABC,
this file contains DEF,
this file contains XYZ,
this file contains KLM
;
I want to have a fileZ that has only (begin search pattern for will be... (2 Replies)
Discussion started by: vbabz
2 Replies
LEARN ABOUT DEBIAN
plan9-grep
GREP(1) General Commands Manual GREP(1)NAME
grep, g - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
g [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines that match the pattern, a regular expression as defined in regexp(7) with
the addition of a newline character as an alternative (substitute for |) with lowest precedence. Normally, each line matching the pattern
is `selected', and each selected line is copied to the standard output. The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-e The following argument is taken as a pattern. This option makes it easy to specify patterns that might confuse argument parsing,
such as -n.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
-f The pattern argument is the name of a file containing regular expressions one per line.
-b Don't buffer the output: write each output line as soon as it is discovered.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'. An expression starting with '*' will treat the rest of the expression as literal characters.
G invokes grep with -n and forces tagging of output lines by file name. If no files are listed, it searches all files matching
*.C *.b *.c *.h *.m *.cc *.java *.cgi *.pl *.py *.tex *.ms
SOURCE
/src/cmd/grep
/bin/g
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(7)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)