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Full Discussion: Function into a condition ?
Top Forums Shell Programming and Scripting Function into a condition ? Post 302780339 by Corona688 on Thursday 14th of March 2013 11:58:22 AM
Old 03-14-2013
Quote:
Originally Posted by pamu
I think function's in bash doesn't accept any variables.
Incorrect, they take parameters just fine.

You call them directly, outside [ ], like you would an external program.

Code:
if g1 $1 $2 $3
then
...
else
...
fi

And your function should use return to give an integer value that if can use in this manner. It's like exit but only quits a function or sourced script instead of the entire program. Zero means success, nonzero means failure, just like the exit status of an external utility. Your EC variable trick works but such indirectness isn't necessary.

Code:
g1 () {
        if [ something ]
        then
                echo "success"
                return 0
        else
                echo "failure"
                return 1
        fi
}

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Time::Seconds(3pm)					 Perl Programmers Reference Guide					Time::Seconds(3pm)

NAME
Time::Seconds - a simple API to convert seconds to other date values SYNOPSIS
use Time::Piece; use Time::Seconds; my $t = localtime; $t += ONE_DAY; my $t2 = localtime; my $s = $t - $t2; print "Difference is: ", $s->days, " "; DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects. Time::Seconds also exports the following constants: ONE_DAY ONE_WEEK ONE_HOUR ONE_MINUTE ONE_MONTH ONE_YEAR ONE_FINANCIAL_MONTH LEAP_YEAR NON_LEAP_YEAR Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print ONE_WEEK->minutes;" METHODS
The following methods are available: my $val = Time::Seconds->new(SECONDS) $val->seconds; $val->minutes; $val->hours; $val->days; $val->weeks; $val->months; $val->financial_months; # 30 days $val->years; The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year. (from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html) AUTHOR
Matt Sergeant, matt@sergeant.org Tobias Brox, tobiasb@tobiasb.funcom.com BalieXXzs SzabieXX (dLux), dlux@kapu.hu LICENSE
Please see Time::Piece for the license. Bugs Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea. perl v5.12.1 2010-04-26 Time::Seconds(3pm)
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