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Top Forums Shell Programming and Scripting Echo not displaying variable in If-Else condition Post 302771923 by RudiC on Friday 22nd of February 2013 06:28:58 AM
Old 02-22-2013
You know you can make THAT statement way more legible and efficient?

Pls post output of echo "$x_oug"
 

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SQLSRV_NUM_FIELDS(3)													      SQLSRV_NUM_FIELDS(3)

sqlsrv_num_fields - Retrieves the number of fields (columns) on a statement

SYNOPSIS
mixed sqlsrv_num_fields (resource $stmt) DESCRIPTION
Retrieves the number of fields (columns) on a statement. PARAMETERS
o $stmt - The statment for which the number of fields is returned. sqlsrv_num_fields(3) can be called on a statement before or after statement execution. RETURN VALUES
Returns the number of fields on success. Returns FALSE otherwise. EXAMPLES
Example #1 sqlsrv_num_fields(3) example <?php $serverName = "serverNamesqlexpress"; $connectionInfo = array( "Database"=>"dbName", "UID"=>"username", "PWD"=>"password"); $conn = sqlsrv_connect( $serverName, $connectionInfo); if( $conn === false ) { die( print_r( sqlsrv_errors(), true)); } $sql = "SELECT * FROM Table_1"; $stmt = sqlsrv_query($conn, $sql); if( $stmt === false) { die( print_r( sqlsrv_errors(), true)); } $numFields = sqlsrv_num_fields( $stmt ); while( sqlsrv_fetch( $stmt )) { // Iterate through the fields of each row. for($i = 0; $i < $numFields; $i++) { { echo sqlsrv_get_field($stmt, $i)." "; } echo "<br />"; } ?> SEE ALSO
sqlsrv_field_metadata(3), sqlsrv_fetch(3), sqlsrv_get_field(3). PHP Documentation Group SQLSRV_NUM_FIELDS(3)
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