Hi,
I have a question on bash. Basically I would like to print a file name using bash. I am actually trying to grep a particular character in sequential files.
I have alot files such that a.txt, b.txt,c.txt...etc.
If I found a certain character, I would print that particular filename.
I... (5 Replies)
Hi all,
I need help in following scenario. I have a file with about 10,000 lines. There are several lines which have word "START" (all upper case) in them. I want to grep line with word "START" and then do the following
1. Print the line number having word "START"
2. Print the next 11 lines.
... (4 Replies)
Hi Guys,
I need to set the value of $7 to zero in case $7 is NULL. I've tried the below command but doesn't work. Any ideas. thanks guys.
MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else { print $7}}' `
Harby. (4 Replies)
I just need to print value 12 digit number after the key *MI*. My big concern is the below lines are not fixed format or length so cant cut based on the position.
XSA*00**00**XZ*DA-Paper*30*942411167****MI*010001990802~AEE
XSA*00**00**ZZ*EA-aper*30*94169****MI*010001960802~SDRE*ER... (7 Replies)
Hi
I have this in my file
2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times.
2011-04-18 15:32:11 system-alert-00012: UDP flood! From xxxxxx to yyyyyyyyyy, int ethernet0/2). Occurred 1 times.
2011-04-18 15:32:11... (9 Replies)
My current code is:
user@ubuntu:~/Desktop$ grep -e "\(packaged by\)\|\(employee\)\|\(file name\)\|\(Total Data (MB) Read\)\|\(Begin Time\)" log.txt
packaged by = Ron Mexico
employee = Michael Vick
file name = Mike_Vick_2011.bat
Total Data (MB) Read: 11.82
Begin Time: 6/13/2011... (8 Replies)
RHEL 5.8
I have a text file like below. I want to grep for a string and then print the next 4 lines including the line with the string I grepped for
For eg:
I want grep for the string HANS and then print the next 4 lines including HANS
$ cat someText.txt
JOHN
NATIONALITY:... (7 Replies)
Discussion started by: omega3
7 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)