awk -F ";" '{if($10>80 && NR>1) print $0 }' txt_file_*
I am using this command to print the lines which has 10th field more then 80 and leaving the first line of the file which is the header.
But this is not working , the first line is is coming as output , please correct me .
thanks (2 Replies)
Hi all,
This should be very easy but I can't figure it out...
I have a file that looks like this:
@SRR057408.1 FW8Y5CK02R652T length=34
AGCAGTGGTATCAACGCAGAGTAAGCAGTGGTAT
+SRR057408.1 FW8Y5CK02R652T length=34
FIIHFF6666?=:88@@@BBD:::?@ABBAAA>8
@SRR057408.2 FW8Y5CK02TBMHV length=52... (1 Reply)
Hi,
Below is the data in a tab limited file
Here ACCENT is just a heading and the line starting with Pcode has the column headers, and there is a 2 lines space between the file header and column header.
I want to print $2, that is Dealer Name
I used the below code
nawk... (1 Reply)
Dear All,
Good Day. I would like to solve the following issue and got some strange results, if anyone could help me in this regard, you are most welcome.
Here is the problem:
I have a file like
Header Value1 Value2 Value3 Value4 Value5 Value6 ... Value9
12.144 6 5 ... (8 Replies)
i have a input of csv file as below but the sequence of column get changed.
I,e it is not necessary that name comes first then age and rest all, it may vary.
name,age,marks,roll,section
kevin,25,80,456,A
Satch,23,56,789,B
Meena,24,78,H245,C
So i want to print that column entires which... (12 Replies)
In the awk below I am trying to print only the header lines starting with # or ## and the lines that $7 is PASS and AF= is less than 5%. The awk does execute but returns an empty file and I am not sure what I am doing wrong. Thank you.
file
... (0 Replies)
I've been struggling with this one for quite a while and cannot seem to find a solution for this find/replace scenario. Perhaps I'm getting rusty.
I have a file that contains a number of metrics (exactly 3 fields per line) from a few appliances that are collected in parallel. To identify the... (3 Replies)
I have a directory of files, I can show the number of lines in each file and order them from lowest to highest with:
wc -l *|sort
15263 Image.txt
16401 reference.txt
40459 richtexteditor.txt
How can I also print the number of unique lines in each file?
15263 1401 Image.txt
16401... (15 Replies)
Discussion started by: spacegoose
15 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)