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Full Discussion: Indirect variables in Bash
Top Forums Shell Programming and Scripting Indirect variables in Bash Post 302769144 by Corona688 on Monday 11th of February 2013 10:12:19 AM
Old 02-11-2013
This is easiest done with read. It's handy because it takes a variable name, which you can construct by any means you want.

Code:
 read $A$B <<<"string"

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DBASE_OPEN(3)								 1							     DBASE_OPEN(3)

dbase_open - Opens a database

SYNOPSIS
int dbase_open (string $filename, int $mode) DESCRIPTION
dbase_open(3) opens a dBase database with the given access mode. Note When safe mode is enabled, PHP checks whether the files or directories being operated upon have the same UID (owner) as the script that is being executed. Note This function is affected by open_basedir. PARAMETERS
o $filename - The name of the database. It can be a relative or absolute path to the file where dBase will store your data. o $mode - An integer which correspond to those for the open() system call (Typically 0 means read-only, 1 means write-only, and 2 means read and write). Note You can't open a dBase file in write-only mode as the function will fail to read the headers information and thus you can't use 1 as $mode. EXAMPLES
Example #1 Opening a dBase database file <?php // open in read-only mode $db = dbase_open('/tmp/test.dbf', 0); if ($db) { // read some data .. dbase_close($db); } ?> RETURN VALUES
Returns a database link identifier if the database is successfully opened, or FALSE if an error occurred. SEE ALSO
dbase_create(3), dbase_close(3). PHP Documentation Group DBASE_OPEN(3)
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