I have been search all over the internet to find a solution to this.
I have a file that looks like:
-a ItemConfig.custom=true
-a Config.custom=true
go -t malu
-t Use=true
I want to get "malu" as output, and the werid thing is the blank before go is neither space nor tab.
what's the sed... (4 Replies)
Hi,
I want to remove all occurances of a character which follows a ^ symbol.
For ex:
This is a Test ^H^@^@^@^@^@^@ File used in VI. ^@^@^B^VDM-BM-$|M-^_M-F^AM-
In the above example, I should remove all characters which follows a ^.
(^H ^@ ^B ^V etc) and It should print This is a Test... (4 Replies)
Hi
I have a list of files in a folder.I have a search pattern in the file name and i want to remove the file with that pattern.How can that be made
List of files
xxxxx.ID1.yyyyy.zzzzz
yyyy.ID2.bbbbb.kkkkk
xxxxx.ID1.yyyyy.zzzzz
yyyy.ID4.bbbbb.kkkkk
xxxxx.ID1.yyyyy.zzzzz... (2 Replies)
i have nasty html file with 2000+ simbols in 1 row...i need to remove whole the code except title="Some title..." and store those into file with titles (the whole text is in variable text)
i've tried something like this:
echo $text | sed 's/.*\(title=\".+\"\).*/\1/' > titles.html
BUT it does... (13 Replies)
Hi,
i want to remove a certain pattern when i type pwd.
pwd will look like this:
..../....../....../Pat_logs/..../....../...../......
the dotted lines are just random directory names,
i want it to remove the "Pat_logs/...../....../....../" part
so for example:
... (5 Replies)
Hi,
I want to search a pattern in a text file and remove another pattern in that file.
my text file look like this
0.000000 1.970000 F 303 -
1.970000 2.080000 VH VH +
2.080000 2.250000 VH VH +
2.250000 2.330000 VH L -
2.330000 2.360000 F H +
2.360000 2.410000 L VL -
2.410000 ... (6 Replies)
Hi I have a file where i want to remove a char before a specific pattern.
exp:
CREATE TABLE
(
A,
B,
C, ----comma needs to be removed
)AS SELECT
A,
B,
C, ----comma needs to be removed
FROM TABLE.
So i want to delete the comma(,) after the C both ways.Pattern can be... (11 Replies)
In the awk below I am trying to remove all lines above and including the pattern Test or Test2. Each block is seperated by a newline and Test2 also appears in the lines to keep but it will always have additional text after it. The Test to remove will not. The awk executed until the || was added... (2 Replies)
Discussion started by: cmccabe
2 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)