hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Hi,
One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT REDHAT
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week. (This is the default.)
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
BSD June 6, 1993 BSD