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Full Discussion: To cut a string based on last index of identifier
Top Forums Shell Programming and Scripting To cut a string based on last index of identifier Post 302761107 by Subbeh on Friday 25th of January 2013 05:43:02 AM
Old 01-25-2013
This will get you the filename:

Code:
sed -e 's#.*/##' -e 's/:.*//' inputfile

Or simply use grep:
Code:
grep -o [^/]*java inputfile

Last edited by Subbeh; 01-25-2013 at 06:53 AM..
 

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LEARN ABOUT X11R4

zgrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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