hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Hi,
One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT OPENSOLARIS
holidays
holidays(4) File Formats holidays(4)NAME
holidays - prime/nonprime table for the accounting system
SYNOPSIS
/etc/acct/holidays
DESCRIPTION
The /etc/acct/holidays file specifies prime time hours and holidays. Holidays and weekends are considered non-prime time hours.
/etc/acct/holidays is used by the accounting system.
All lines beginning with an * are comments.
The /etc/acct/holidays file consists of two sections. The first non-comment line defines the current year and the start time of prime and
non-prime time hours, in the form of:
current_year prime_start non_prime_start
Specify prime_start and non_prime_start times in the range of 0000 to 2400.
The remaining non-comment lines define the holidays in the form of:
month/day company_holiday
Of these two fields, only the month/day is actually used by the accounting system programs.
The /etc/acct/holidays file must be updated every year.
EXAMPLES
Example 1 An Example of the /etc/acct/holidays File
The following is an example of the /etc/acct/holidays file:
* Prime/Nonprime Table for the accounting system
*
* Curr Prime Non-Prime
* Year Start Start
*
1991 0830 1800
*
* only the first column (month/day) is significant.
*
* month/day Company Holiday
*
1/1 New Years Day
5/30 Memorial Day
7/4 Indep. Day
9/5 Labor Day
11/24 Thanksgiving Day
11/25 day after Thanksgiving
12/25 Christmas
12/26 day after Christmas
SEE ALSO acct(1M)SunOS 5.11 18 Aug 2008 holidays(4)