|
|
Sponsored Content
Top Forums
UNIX for Advanced & Expert Users
How to get the days of Particular date?
Post 302759811 by Venkatesh1 on Wednesday 23rd of January 2013 01:09:56 AM
01-23-2013
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Discussion started by: ladtony
17 Replies
2. Shell Programming and Scripting
i need a script that can tell me the date 2 days ago or 3 days ago.
please help (7 Replies)
Discussion started by: tomjones
7 Replies
3. Shell Programming and Scripting
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies
4. Shell Programming and Scripting
Hello Experts,
How do i get date after 5 days from current date in YYYYMMDD format?
How do you compare date in YYYYMMDD format?
Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies
5. Shell Programming and Scripting
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Discussion started by: Himanshu_soni
3 Replies
6. Shell Programming and Scripting
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies
7. Shell Programming and Scripting
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Discussion started by: kokoro
1 Replies
8. Shell Programming and Scripting
Hi,
One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
Discussion started by: juzz4fun
4 Replies
9. UNIX for Beginners Questions & Answers
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
Discussion started by: dia
1 Replies
10. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
arbitron
ARBITRON(8) System Manager's Manual ARBITRON(8) * NAME
arbitron - arbitron mailboxes SYNOPSIS
arbitron [ -C config-file ] [ -o ] [ -u ] [ -l ] [ -p months ] [ -d days | -D mmddyyyy[:mmddyyyy] ] mailbox... DESCRIPTION
Arbitron collects and reports readership statistics for mailboxes on the server. It also optionally prunes the mailboxes of Seen state for dormant users. Arbitron produces one line of output per mailbox, reporting the mailbox name followed by a space, followed by the number of readers (and if -u is specified, followed by a colon and a comma-separated list of the readers userids), and if -o is not specified, another space and the number of subscribers (and if -u is specified, followed by a colon and a comma-separated list of the subscribers userids). IMPORTANT: This format is subject to change in future versions. Each "reader" is a distinct authentication identity which has "s" rights to the mailbox and which has SELECTed the mailbox within either the past days days or the specified date range. Users are not counted as reading their own personal mailboxes. Personal mailboxes are not reported unless there is at least one reader other than the mailboxes owner. Arbitron reads its configuration options out of the imapd.conf(5) file unless specified otherwise by -C. OPTIONS
-C config-file Read configuration options from config-file. -o "old way" -- do not report subscribers. -u Report userids in addition to the count(s). -l Enable long reporting (comma delimited table consisting of mbox, userid, r/s, start time, end time). -d days Count as a reader an authentication identity which has SELECTed the mailbox within days days. Default is 30. -D mmddyyyy[:mmddyyyy] Count as a reader an authentication identity which has SELECTed the mailbox within the given date range. The start date and optional end date are specified as 2-digit month of the year, 2-digit day of the month, and 4-digit year. If the end date is not specified, then the current system time is used as the end time. -p months Prune Seen state for users who have not SELECTed the mailbox within months months. Default is infinity. FILES
/etc/imapd.conf CMU
Project Cyrus ARBITRON(8)