What is the output of the following program considering an x86 based parameter passing sequence where stack grows towards lower memory addresses and that arguments are evaluated from right to left:
int i=10;
int f1()
{
static int i = 15;
printf("f1:%d ", i);
return i--;
}
main()
{... (2 Replies)
How to print output in following format?
A..................ok
AA................ok
AAA..............ok
AAAAAA........ok
"ok" one under one (4 Replies)
hi i am using printf in a script and it is not printing negative values..i have to use printf to get rid of the newline..here is my code:
fin=`echo $a - $b | bc`
printf "${fin}," >> test
these statements are in a loop. here is what i get when i try to subtract 4 from 8:
./scr1: line... (2 Replies)
Hello everybody,
I would like to understand why the printf function is returning me an octal value with this command :
printf %4.4d 0010 returns 0008
printf %4.4d 10 returns 0010
Thanks for help. (3 Replies)
Hi,
I have just completed my first script (:D) and now i just need to format it with printf.
This is what I have:
#!/bin/ksh
TOTB=0
TOTF=0
TOTI=0
HOST=`hostname`
echo " FSYSTEM BLKS FREE INUSE MOUNTEDON"
df -m | grep -v ":"|grep -v Free|grep -v "/proc"| while read FSYSTEM... (2 Replies)
Target file contains short text (never more than 1 line) and filenames.
The format is, e.g.,:
TEXT1
filename1
TEXT2
TEXT3
filename3dddd
filename3dddd
TEXT4
filename4
TEXT5
filename5dddd
filename5dddd
filename5
where dddd is a random 4-digit whole number.
Desired output: (4 Replies)
Dear all,
I have the following question. Let's say that I have the following script
#!/bin/bash
value=0.4987865
a=` printf "%6.2f" $value `
b=`echo $value + $value | bc -l`
echo $a
echo $b
exit
And the exit is:
0,00
.9975730
Thus, the problem is that the printf order does not... (2 Replies)
hello all, i came accross an aptitude question ..
int
main()
{
int a = 10, b = 20, c = 30;
printf("%d\t%d\t%d");
}
it gives output
30 20 10
what is the reason of such behaviour of printf().
thank you. (7 Replies)
Hello, this is my first time on the forum. I seem to not have the ability to start a new thread. However, I have a very simple question. I am trying to write a script I have to use printf to say "My name is myname (pulled from $USER) . it works with echo, but with printf the $USER... (2 Replies)
I am running plsql using printf on a shell, but i am getting some strange error, can someone point what exactly am i missing,
$ echo $SHELL
/bin/bash
$ printf "
> SET serveroutput ON trimspool on feed off echo off
> declare
> p_val number;
> d_val varchar2(10);
> begin
> SELECT... (1 Reply)
Discussion started by: kamauv234
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)