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Top Forums Shell Programming and Scripting Awk: How to get an awk variable out to the shell, using system() ? Post 302740451 by DerekAsirvadem on Thursday 6th of December 2012 07:53:56 AM
Old 12-06-2012
Quote:
Originally Posted by Scrutinizer
You need to place the variable outside the double quotes
That was so simple ! Thanks.

But I do not see how that is "outside the double quotes". For the benefit of the understanding of others, that is "concatenate the string before submitting it to system()". And my concern about informing the shell re awk vars, is a non-issue.
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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