12-02-2012
Hi Rudi
I have to fetch above mentioned bold headings in my first post as columns in my expected output.
This input file is sample of my big input file which contain many drug cards
So,
My out put shoulbe like following six coulmns
F2 lepirudin refuldan approved " sentence under indication" "sentence under machanism of action"
As my real input file is big so there will be many rows with different names like this and with my current code these rows are overlapping!
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LEARN ABOUT DEBIAN
cdbtrf
CDBTRF - compute an LU factorization of a real m-by-n band matrix
A without using partial pivoting or row interchanges SUBROUTINE
CDBTRF( M, N, KL, KU, AB, LDAB, INFO )
INTEGER INFO, KL, KU, LDAB, M, N
COMPLEX AB( LDAB, * ) Cdbtrf computes an LU factorization of
a real m-by-n band matrix A without using partial pivoting or row
interchanges.
This is the blocked version of the algorithm, calling Level 3
BLAS.
M
(input) INTEGER The number of rows of the matrix A. M >=
0. N (input) INTEGER The number of columns of the matrix
A. N >= 0. KL (input) INTEGER The number of subdiagonals
within the band of A. KL >= 0. KU (input) INTEGER The num-
ber of superdiagonals within the band of A. KU >= 0. AB
(input/output) REAL array, dimension (LDAB,N) On entry, the ma-
trix A in band storage, in rows KL+1 to 2*KL+KU+1; rows 1 to KL
of the array need not be set. The j-th column of A is stored in
the j-th column of the array AB as follows: AB(kl+ku+1+i-j,j) =
A(i,j) for max(1,j-ku)<=i<=min(m,j+kl)
On exit, details of the factorization: U is stored as an upper
triangular band matrix with KL+KU superdiagonals in rows 1 to
KL+KU+1, and the multipliers used during the factorization are
stored in rows KL+KU+2 to 2*KL+KU+1. See below for further de-
tails. LDAB (input) INTEGER The leading dimension of the ar-
ray AB. LDAB >= 2*KL+KU+1. INFO (output) INTEGER = 0: suc-
cessful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = +i, U(i,i) is exactly zero. The factorization has
been completed, but the factor U is exactly singular, and divi-
sion by zero will occur if it is used to solve a system of equa-
tions. The band storage scheme is illustrated by the following
example, when M = N = 6, KL = 2, KU = 1:
On entry: On exit:
* a12 a23 a34 a45 a56 * u12 u23 u34 u45 u56
a11 a22 a33 a44 a55 a66 u11 u22 u33 u44 u55 u66
a21 a32 a43 a54 a65 * m21 m32 m43 m54 m65 *
a31 a42 a53 a64 * * m31 m42 m53 m64 * *
Array elements marked * are not used by the routine.