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Top Forums UNIX for Dummies Questions & Answers Passing values from file into array in Bash Post 302732751 by RudiC on Monday 19th of November 2012 05:52:17 AM
Old 11-19-2012
Try this; it works in my linux/bash system:
Code:
$ while read a; do eval row$((i++))="($a)"; done <file
$ for j in row{0..2}; do for ((i=0;i<4;i++)); do  eval col$i[${j/row/}]=\${$j[$i]} ;done; done
$ echo ${row0[@]}
1 name1 a first
$ echo ${row1[@]}
2 name2 b second
$ echo ${row2[@]}
3 name3 c third
$ echo ${col0[@]}
1 2 3
$ echo ${col1[@]}
name1 name2 name3
$ echo ${col2[@]}
a b c
$ echo ${col3[@]}
first second third

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IBASE_FETCH_ASSOC(3)							 1						      IBASE_FETCH_ASSOC(3)

ibase_fetch_assoc - Fetch a result row from a query as an associative array

SYNOPSIS
array ibase_fetch_assoc (resource $result, [int $fetch_flag]) DESCRIPTION
Fetch a result row from a query as an associative array. ibase_fetch_assoc(3) fetches one row of data from the $result. If two or more columns of the result have the same field names, the last column will take precedence. To access the other column(s) of the same name, you either need to access the result with numeric indices by using ibase_fetch_row(3) or use alias names in your query. PARAMETERS
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Returns an associative array that corresponds to the fetched row. Subsequent calls will return the next row in the result set, or FALSE if there are no more rows. SEE ALSO
ibase_fetch_row(3), ibase_fetch_object(3). PHP Documentation Group IBASE_FETCH_ASSOC(3)
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