Hi,
This is the format of the file that i have
StartDate:10/01/06
EndDate :10/02/06
Cno Ccode
1 10
2 11
StartDate:10/03/06
EndDate :10/04/06
Cno Ccode
2 13
4 12
StartDate:10/01/06
EndDate :10/02/06 (5 Replies)
Hi All,
I would like to have a script which is able to perform the below.
Print the whole row if column1 which is "0001" for the below example is the first occurrence. Subsequent "0001" occurrence will not be printed out and so on.
Can any expert help ?
Input:
0001 k= 40
0001 k= 2... (7 Replies)
Hello All,
Bash Version: 4.1.10(1)
I'm trying to "verify" some user input. The User input will contain the "Absolute Path" a "Command" and any "Options"
of that Command.
For Example, say the user's input is:
user_input="/usr//local/myExample/check_process -p 'java' -w 10 -c 20"
I... (6 Replies)
Hi,
I have a file, which contains the following log data.
I am trying to print fromt he file the following data:
I have tried using sed, but I am getting from the first pattern
Thanks for your help. (5 Replies)
Hi,
Do anybody know how to use awk to count the pattern at specific column?
Input file
M2A928K 419 ath-miR159a,gma-miR159a-3p,ptc-miR159a 60 miR235a
.
.
Output file
M2A928K 419 ath-miR159a,gma-miR159a-3p,ptc-miR159a 60 miR235a 3
.
.
I plan to count how many "miR" in column 3... (2 Replies)
Hi,
I have a simple problem but i guess stupid enough to figure it out. i have thousands rows of data. and i need to find match patterns of two columns and print the number of rows. for example:
inputfile
abd abp 123
abc abc 325
ndc ndc 451
mjk lkj... (3 Replies)
Hi,
I have a input file(text file) with the following lines.
0x000000 0x5a80 0x0060 BRA.l 0x60 ;file:UserCall.s ;function:_user_call_table ;C_sourceLine:24
0x000002 0x1bc5 RETI ;file:UserCall.s ;function:_user_call_table ;C_sourceLine:30
0x000003 0x6840 MOV R0L,R0L ;file:UserCall.s... (6 Replies)
Hi folks,
I have a file with lots of lines in a text file,i need to print the occurence number after sorting based on the first column as shown below, thanks in advance.
sam,dallas,20174
sam,houston,20175
sam,atlanta,20176
jack,raleigh,457865
jack,dc,7845
john,sacramento,4567
... (4 Replies)
Discussion started by: tech_frk
4 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)