Sponsored Content
Full Discussion: awk command
Top Forums Shell Programming and Scripting awk command Post 302639991 by guruprasadpr on Monday 14th of May 2012 12:54:10 AM
Old 05-14-2012
Hi

In the pattern /sa[kx]s*ena/, s* indicates 0 or more occurrence of s. As per this definition, the output which you got is fine.

Guru.
This User Gave Thanks to guruprasadpr For This Post:
 

8 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

assign a command line argument and a unix command to awk variables

Hi , I have a piece of code ...wherein I need to assign the following ... 1) A command line argument to a variable e.g origCount=ARGV 2) A unix command to a variable e.g result=`wc -l testFile.txt` in my awk shell script When I do this : print "origCount" origCount --> I get the... (0 Replies)
Discussion started by: sweta_doshi
0 Replies

2. Shell Programming and Scripting

awk/sed Command : Parse parameter file / send the lines to the ksh export command

Sorry for the duplicate thread this one is similar to the one in https://www.unix.com/shell-programming-scripting/88132-awk-sed-script-read-values-parameter-files.html#post302255121 Since there were no responses on the parent thread since it got resolved partially i thought to open the new... (4 Replies)
Discussion started by: rajan_san
4 Replies

3. UNIX for Dummies Questions & Answers

Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
Discussion started by: JasonHamm
2 Replies

4. Shell Programming and Scripting

awk command for simple join command but based on 2 columns

input1 a_a a/a 10 100 a1 a_a 20 200 b1 b_b 30 300 input2 a_a a/a xxx yyy a1 a1 lll ppp b1 b_b kkk ooo output a_a a/a 10 100 xxx yyy (2 Replies)
Discussion started by: ruby_sgp
2 Replies

5. Shell Programming and Scripting

awk command in script gives error while same awk command at prompt runs fine: Why?

Hello all, Here is what my bash script does: sums number columns, saves the tot in new column, outputs if tot >= threshold val: > cat getnon0file.sh #!/bin/bash this="getnon0file.sh" USAGE=$this" InFile="xyz.38" Min="0.05" # awk '{sum=0; for(n=2; n<=NF; n++){sum+=$n};... (4 Replies)
Discussion started by: catalys
4 Replies

6. Shell Programming and Scripting

awk command to compare a file with set of files in a directory using 'awk'

Hi, I have a situation to compare one file, say file1.txt with a set of files in directory.The directory contains more than 100 files. To be more precise, the requirement is to compare the first field of file1.txt with the first field in all the files in the directory.The files in the... (10 Replies)
Discussion started by: anandek
10 Replies

7. Shell Programming and Scripting

Multiple command execution inside awk command during xml parsing

below is the output xml string from some other command and i will be parsing it using awk cat /tmp/alerts.xml <Alert id="10102" name="APP-DS-ds_ha-140018-componentFailure-S" alertDefinitionId="13982" resourceId="11427" ctime="1359453507621" fixed="false" reason="If Event/Log Level(ANY) and... (2 Replies)
Discussion started by: vivek d r
2 Replies

8. Shell Programming and Scripting

Pass awk field to a command line executed within awk

Hi, I am trying to pass awk field to a command line executed within awk (need to convert a timestamp into formatted date). All my attempts failed this far. Here's an example. It works fine with timestamp hard-codded into the command echo "1381653229 something" |awk 'BEGIN{cmd="date -d... (4 Replies)
Discussion started by: tuxer
4 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:24 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy