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Top Forums Shell Programming and Scripting Grepping for hex characters - explanation? Post 302491084 by mregine on Wednesday 26th of January 2011 04:49:23 PM
Old 01-26-2011
Grepping for hex characters - explanation?

Hello,

Yesterday I was looking for a way to grep for a tab in the shell, and found this solution in several places:
Code:
grep $'[\x09]a[\x09]' # Grep for the letter 'a' between two tabs

I'm fine with most of this, but I don't understand what the $ (dollar sign) before the first quote does. It doesn't work without, but I couldn't find any explanation in the grep man or info pages. The only mention of $ there is as a meta-character that matches the end of a regular expression.

Can someone explain and/or point me to other documentation where I can read it up?

Thanks!
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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