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Full Discussion: Exit status of grep
Top Forums Shell Programming and Scripting Exit status of grep Post 302402175 by frans on Tuesday 9th of March 2010 05:20:27 AM
Old 03-09-2010
Quote:
Originally Posted by zaxxon
Assigning the substituted output of a command to a variable will simply contain it's output, ie. the pattern grep -o found or not. It does not contain the return code of the grep!
The variable contains the output but the return code corresponds to the return code of the last command (grep). Try to print $? and you'll see what happens.

Quote:
Originally Posted by zaxxon
It doesn't have anything to do with the type of how it is substituted ie. double `or $().
Right, it just makes it more readable and permits the nesting.
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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