I write a sh script that zip and copy to tape all files that older then 2 hours.
1. The way I choose is - touch a file with "now - 2 hours", then use fine with '! -newer'
2. Do you have any other idea to do it ?
tnx. (1 Reply)
I Have a long file like this
123122312 05/06/12
123123456 05/06/14
I want to take the difference of dates in two lines & print difference sidewise for the whole long files.
Pl help me out. (1 Reply)
I have the script which appends month and year to the name of the
file. Now every time when I append the month-year combination I
have to subtract 2 months from the current date and then append
it, since we are sending our vendor 2 months prior worth of data
eveytime.
#! /usr/bin/ksh
... (5 Replies)
the given time is:
12:13:00
how do i subtract a 10 minutes from any given time?
date '12:13:00' '-10 min'
also tried this:
date +12:13:00 '-10 min' (2 Replies)
I have a file with name and date---
$ cat file.log
userA 01-06-2014
userB 25-05-2014
userC 16-05-2014
userC 01-03-2014
I want to search for the current date and get the name for that date. If current date is not found, go back 1 day and search and so on till it finds the... (2 Replies)
Hi,
I am reading a particular date from a file using below command
WFLWDATE=$(sed '2q;d' FileA.prm)
The echo command outputs the correct date in variable WFLWDATE
Now I want to subtract 5 minutes from this variable. I am on AIX and unable to get anything working as expected.
Can you... (1 Reply)
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT SUSE
date::manip::changes6
Date::Manip::Changes6(3) User Contributed Perl Documentation Date::Manip::Changes6(3)NAME
Date::Manip::Changes6 - backward incompatible changes in Date::Manip 6.xx
SYNOPSIS
This describes all backwards incompatible changes made to the Date::Manip module starting at version 6.00.
DESCRIPTION
For the most part, Date::Manip has remained backward compatible at every release, but occasionally, a change is made which is backward
incompatible. These are documented here. Major changes are marked with asterisks.
6.05
%z format
In Date::Manip 5.xx, the %z format in UnixDate printed the offset in the form -0500. In 6.00, I changed that to -05:00:00, but this
broke RFC 822 compliance.
I've changed %z back to -0500, and introduced a new format (%N) which returns -05:00:00.
Incidentally, this is the LAST unused letter, so I am now going to have to either stop adding formats, or add some extended format
syntax. Not sure yet which, but this may involve a backwards incompatible change in the future.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip - main module documentation
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.12.1 2010-01-12 Date::Manip::Changes6(3)