Quote:

Originally Posted by fpmurphy Humm, I have looked at this shell script a few times and scratched my head. You set the variable 'q' to a string Code: q="scale=3; $zpos" yet you expect to be able to subtract a number from it Code: zposition=$q-$f How is this meant to work?

Hi,

I revisited it too and scratched my head as well! There's a bug in the script...if firstslice is bigger than lastslice it won't work. So I've tried a different tack using awk.

as a reminder, this is what I want to do; I have a list of files:

Code:

 
sl40_z11.70.txt
sl41_z11.40.txt
sl42_z11.10.txt
sl43_z10.80.txt

cp sl40_z11.70.txt sl40_z11.70.dat
cp sl41_z11.40.txt sl41_z11.40.dat
cp sl42_z11.10.txt sl42_z11.10.dat
cp sl43_z10.80.txt sl43_z10.80.dat

 
#!/bin/sh
#
echo -n "....enter first slice number....."; read firstslice
echo -n "....enter last slice number....."; read lastslice
#
echo -n "....enter first Z-coordinate position....."; read zpos
#sliceDiff=0.3
#
loopNumber=$[($lastslice - $firstslice)+1]
echo "loopNumber is $loopNumber"
echo firstslice no. is $firstslice
for ((k=$firstslice;k<=$lastslice; k++)); do 
r=$[k]
echo "$firstslice $r $zpos" | awk '{print $3-(($2-$1)*0.3)}'
#echo "$firstslice $r $zpos" | awk '{print $i}' sl$2_z[$3-(($2-$1)*0.3)].txt > xxxx.dat
done