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Old 07-02-2009
jolecanard jolecanard is offline
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Join Date: Sep 2008
Posts: 36
Make a list in bash out of arguments

Hello,

I have a very stupid/simple problem, but for some reason I cannot figure out...and I need your help!

I am writting a bash scrip that should be executed using "my_script X Y Z T" where X Y Z and T can be any string, but there can be any number of arguments.

I want my script to do a list from these inputs:
Code:
#!/bin/bash
 
i=1
while [ $i -le $# ]
do
list=$list" ./myfile."$i
i=`expr $i + 1`
done
echo $list
Using the above script, I got:
./myfile.1 ./myfile.2 ./myfile.3 ./myfile.4
instead of:
./myfile.X ./myfile.Y ./myfile.Z ./myfile.T


Thanks for your help