What if the number of lines of the original file is unknown ?
In my example I gave 3 lines but it can be anything between 1 and 20 lines.
In this case you will have to have some indication for a "record" being complete. Maybe you will need some record starting criteria too, for which one could match. Provide some data and i will provide some solution.
Quote:
Originally Posted by Browser_ice
I tried the combinations below which do not change anything or are not recognized
This is just a way to enter non-printing (control-) characters into vi: enter input mode, press "CTRL-V", then press CTRL-M (for example for "^M"). You should be still in input mode and see "^M" under the cursor.
Quote:
sed 's/.$//' does remove the ^M at the end of each line but then it is still a multi-line format.
It removes the last character in a line, regardless which character this is - this is the problem. You have to specifically match "^M" (CTRL-M) and throw that out. You can throw out linefeeds by searching for "\n". Try the following with some test file:
to see the effect: two lines combined to one and the linefeed is replaced by an at.
[quote]Is there a way to find out in VI what is the ascii value of the character under the cursor ?[/qoute]
Hi,
I have a situation where I want to replace some occurrences of ".jsp" into ".html" inside a text file.
For Example:
If a pattern found like <a href="http://www.mysite.com/mypage.jsp"> it should be retained.
But if a pattern found like <a href="../mypage.jsp"> it should be changed to... (4 Replies)
Hi I'm trying to replace text in a file based upon a pattern.
The pattern I'm looking for is:
<styleURL>#style0002</styleURL>
<name>#######6105#######</name>The # are seven alphanumeric characters before and after 6105.
I need it to replace that with this recursively:
... (4 Replies)
Hi
I need to create multiple text files from onc text file on AIX. The data of text files is as below:
**********************************************
**********************************************
DBVERIFY: Release 10.2.0.4.0 - Production on Tue Nov 10 13:45:42 2009
Copyright (c) 1982,... (11 Replies)
i am editing a big log file with the following pattern:
Date: xxxx Updated: name
Some log file text here
Date: eee Updated: ny
Some log file text here
Basically i want to remove all the text in a line before the "Updated" pattern. I sill want to print the other... (4 Replies)
Can someone help me with a sed command:
There will be multiple occurences in a file that look like this:
MyFunction(12c34r5)
and I need to replace that with just the 12c34r5 for every occurrence. The text between the parentheses will be different on each occurrence, so I can't search for that.... (4 Replies)
HI Folks,
I'm looking for a solution for this issue.
I want to find the Pattern 0/ and replace it with /. I'm just removing the leading zero. I can find the Pattern but it always puts literal value as a replacement.
What am I missing??
sed -e s/0\//\//g File1 > File2
edit by... (3 Replies)
I have a sample text format as given below
<Text Text_ID="10155645315851111_10155645333076543" From="460350337461111" Created="2011-03-16T17:05:37+0000" use_count="123">This is the first text</Text>
<Text Text_ID="10155645315851111_10155645317023456" From="1626711840902323"... (3 Replies)
i have a file which contains data seperated by comma. i want to replace text after 3rd occurrence of a comma.
the input file looks like this
abcdef,11/02/2015 11:55:47,1001,1234567812345678,12364,,abc
abcdefg,11/02/2015 11:55:47,01,1234567812345678,123,,abc
abcdefhih,11/02/2015... (4 Replies)