What if the number of lines of the original file is unknown ?
In my example I gave 3 lines but it can be anything between 1 and 20 lines.
In this case you will have to have some indication for a "record" being complete. Maybe you will need some record starting criteria too, for which one could match. Provide some data and i will provide some solution.
Quote:
Originally Posted by Browser_ice
I tried the combinations below which do not change anything or are not recognized
This is just a way to enter non-printing (control-) characters into vi: enter input mode, press "CTRL-V", then press CTRL-M (for example for "^M"). You should be still in input mode and see "^M" under the cursor.
Quote:
sed 's/.$//' does remove the ^M at the end of each line but then it is still a multi-line format.
It removes the last character in a line, regardless which character this is - this is the problem. You have to specifically match "^M" (CTRL-M) and throw that out. You can throw out linefeeds by searching for "\n". Try the following with some test file:
to see the effect: two lines combined to one and the linefeed is replaced by an at.
[quote]Is there a way to find out in VI what is the ascii value of the character under the cursor ?[/qoute]
Hi,
I have a situation where I want to replace some occurrences of ".jsp" into ".html" inside a text file.
For Example:
If a pattern found like <a href="http://www.mysite.com/mypage.jsp"> it should be retained.
But if a pattern found like <a href="../mypage.jsp"> it should be changed to... (4 Replies)
Hi I'm trying to replace text in a file based upon a pattern.
The pattern I'm looking for is:
<styleURL>#style0002</styleURL>
<name>#######6105#######</name>The # are seven alphanumeric characters before and after 6105.
I need it to replace that with this recursively:
... (4 Replies)
Hi
I need to create multiple text files from onc text file on AIX. The data of text files is as below:
**********************************************
**********************************************
DBVERIFY: Release 10.2.0.4.0 - Production on Tue Nov 10 13:45:42 2009
Copyright (c) 1982,... (11 Replies)
i am editing a big log file with the following pattern:
Date: xxxx Updated: name
Some log file text here
Date: eee Updated: ny
Some log file text here
Basically i want to remove all the text in a line before the "Updated" pattern. I sill want to print the other... (4 Replies)
Can someone help me with a sed command:
There will be multiple occurences in a file that look like this:
MyFunction(12c34r5)
and I need to replace that with just the 12c34r5 for every occurrence. The text between the parentheses will be different on each occurrence, so I can't search for that.... (4 Replies)
HI Folks,
I'm looking for a solution for this issue.
I want to find the Pattern 0/ and replace it with /. I'm just removing the leading zero. I can find the Pattern but it always puts literal value as a replacement.
What am I missing??
sed -e s/0\//\//g File1 > File2
edit by... (3 Replies)
I have a sample text format as given below
<Text Text_ID="10155645315851111_10155645333076543" From="460350337461111" Created="2011-03-16T17:05:37+0000" use_count="123">This is the first text</Text>
<Text Text_ID="10155645315851111_10155645317023456" From="1626711840902323"... (3 Replies)
i have a file which contains data seperated by comma. i want to replace text after 3rd occurrence of a comma.
the input file looks like this
abcdef,11/02/2015 11:55:47,1001,1234567812345678,12364,,abc
abcdefg,11/02/2015 11:55:47,01,1234567812345678,123,,abc
abcdefhih,11/02/2015... (4 Replies)
hi unix expert
is there any command in linux to repace a pattern in the text to another pattern?
many thanks
samad (2 Replies)
Discussion started by: abdossamad2003
2 Replies
LEARN ABOUT REDHAT
unix2dos
unix2dos(1) General Commands Manual unix2dos(1)NAME
unix2dos - UNIX to DOS text file format converter
SYNOPSYS
unix2dos [options] [-c convmode] [-o file ...] [-n infile outfile ...]
Options:
[-hkqV] [--help] [--keepdate] [--quiet] [--version]
DESCRIPTION
This manual page documents unix2dos, the program that converts text files in UNIX format to DOS format.
OPTIONS
The following options are available:
-h --help
Print online help.
-k --keepdate
Keep the date stamp of output file same as input file.
-q --quiet
Quiet mode. Suppress all warning and messages.
-V --version
Prints version information.
-c --convmode convmode
Sets conversion mode. Simulates unix2dos under SunOS.
-o --oldfile file ...
Old file mode. Convert the file and write output to it. The program default to run in this mode. Wildcard names may be used.
-n --newfile infile outfile ...
New file mode. Convert the infile and write output to outfile. File names must be given in pairs and wildcard names should NOT be
used or you WILL lost your files.
EXAMPLES
Get input from stdin and write output to stdout.
unix2dos
Convert and replace a.txt. Convert and replace b.txt.
unix2dos a.txt b.txt
unix2dos -o a.txt b.txt
Convert and replace a.txt in ASCII conversion mode. Convert and replace b.txt in ISO conversion mode.
unix2dos a.txt -c iso b.txt
unix2dos -c ascii a.txt -c iso b.txt
Convert and replace a.txt while keeping original date stamp.
unix2dos -k a.txt
unix2dos -k -o a.txt
Convert a.txt and write to e.txt.
unix2dos -n a.txt e.txt
Convert a.txt and write to e.txt, keep date stamp of e.txt same as a.txt.
unix2dos -k -n a.txt e.txt
Convert and replace a.txt. Convert b.txt and write to e.txt.
unix2dos a.txt -n b.txt e.txt
unix2dos -o a.txt -n b.txt e.txt
Convert c.txt and write to e.txt. Convert and replace a.txt. Convert and replace b.txt. Convert d.txt and write to f.txt.
unix2dos -n c.txt e.txt -o a.txt b.txt -n d.txt f.txt
DIAGNOSTICS BUGS
The program does not work properly under MSDOS in stdio processing mode. If you know why is that so, please tell me.
AUTHOR
Benjamin Lin - ( blin@socs.uts.edu.au )
MISCELLANY
Tested environment:
Linux 1.2.0 with GNU C 2.5.8
SunOS 4.1.3 with GNU C 2.6.3
MS-DOS 6.20 with Borland C++ 4.02
Suggestions and bug reports are welcome.
SEE ALSO dos2unix(1)1995.03.31 unix2dos v2.2 unix2dos(1)