Hey ,
I'm trying to perform the following command, however it cannot read the variable assigned earlier. I'm not sure why this happen. Please help thanks
while :
do
echo "what's ur name? (if none just press )"
read name
changeName = echo $name | sed "s/on/ey/"
echo $changeName #this... (8 Replies)
I am making of a script that will go through a couple of for loops and create file names based on the values in that loop, however the variable that combines everything is not getting assigned properly:
#! /bin/bash
for imod in K33_j1b_WS9_6
do
for emod in mb2A mb2C mb3A mb3C mb4A... (1 Reply)
Hi,
i'm posting this in the Solaris forum although maybe it should be better in the General unix forum, I'm formatting an output witht he following command:
crontab -l | grep GBOUAT8 | grep UTP | grep -i stop | sed 's/\\//'
08 2 * * 2-6 /apps/sum_glob/gbo_uat/sparse/bin/dmg_cronlaunch -ENVI... (2 Replies)
The requirement is, there is a log file which contains a huge data. i need to get a particular field out of it by searching with another field.
ex:
2011-03-28 13:00:07,423 : millis=231 q={ call get_data_account(?,?,?,?,?) }, params=
i need to search for the word "get_data_account" in file... (1 Reply)
I am trying to check whether a variable has been assigned on the command line or not.
Here is what I did:
#!/usr/bin/bash
if( $variable == '\0')
{
print "variable was not assigned"
exit
}
else
NF = 2 {print $1, ""}
exit
fi
awk -f question1.awk variable = 58 letters.txt.
So... (3 Replies)
I am more of a newbie, but wanted to post this in this forum as I was afraid no one would look at it in unix forums as it concerns shell scripting. I have a shell script that now runs fine with the exclusion of one line:
x=`su nbadmin -c "ssh -t servery /usr/openv/netbackup/bin/bplist -C... (7 Replies)
I want to do 2 things in single line that is evaluating a command to get return code and store $2 of awk if the command exit code is 0.
eval "ade desc ${filename}@@/<branch_name> | grep Version | awk '{print $2}' 2>&1 1>/dev/null"
ret=$?
echo "$ret $val"
if
then
... (3 Replies)
Experts,
I'm having problems with the code below.
I'm trying to test $var2 for two different regexs.
I thought it could be done per below, but I'm getting the following error when running.
$ ./test.pl b fed50c0100****
Unescaped left brace in regex is deprecated, passed through in regex; marked... (2 Replies)
Discussion started by: timj123
2 Replies
LEARN ABOUT PHP
is_scalar
IS_SCALAR(3) 1 IS_SCALAR(3)is_scalar - Finds whether a variable is a scalarSYNOPSIS
bool is_scalar (mixed $var)
DESCRIPTION
Finds whether the given variable is a scalar.
Scalar variables are those containing an integer, float, string or boolean. Types array, object and resource are not scalar.
Note
is_scalar(3) does not consider resource type values to be scalar as resources are abstract datatypes which are currently based on
integers. This implementation detail should not be relied upon, as it may change.
Note
is_scalar(3) does not consider NULL to be scalar.
PARAMETERS
o $var
- The variable being evaluated.
RETURN VALUES
Returns TRUE if $var is a scalar, FALSE otherwise.
EXAMPLES
Example #1
is_scalar(3) example
<?php
function show_var($var)
{
if (is_scalar($var)) {
echo $var;
} else {
var_dump($var);
}
}
$pi = 3.1416;
$proteins = array("hemoglobin", "cytochrome c oxidase", "ferredoxin");
show_var($pi);
show_var($proteins)
?>
The above example will output:
3.1416
array(3) {
[0]=>
string(10) "hemoglobin"
[1]=>
string(20) "cytochrome c oxidase"
[2]=>
string(10) "ferredoxin"
}
SEE ALSO is_float(3), is_int(3), is_numeric(3), is_real(3), is_string(3), is_bool(3), is_object(3), is_array(3).
PHP Documentation Group IS_SCALAR(3)