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Full Discussion: sizeof an array of structure without using 'sizeof' operator
Top Forums Programming sizeof an array of structure without using 'sizeof' operator Post 302302154 by pshaikh on Monday 30th of March 2009 08:32:58 AM
Old 03-30-2009
Yes, I guess you can do; something like

Code:
#pragma pack(1)
#include <header.h> // Header file which contain opaque structure definition
int main()
{
     char begin;
     struct unknown_structure array[100];
     char end;

     printf("Size of structure = %u ", (&begin > &end) ? (&begin - &end - 1)/100 : (&end - &begin - 1)/100);

     return 0;
}

Let me know the output.
This may not be accurate, refer to alignment and structure padding
 

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LEARN ABOUT CENTOS

std::tuple

std::tuple< _Elements >(3)				     Library Functions Manual					std::tuple< _Elements >(3)

NAME

       std::tuple< _Elements > -

SYNOPSIS

       Inherits std::_Tuple_impl< 0, _Elements...>.

   Public Member Functions
       constexpr tuple (const _Elements &...__elements)
       template<typename... _UElements, typename  = typename
	   enable_if<__and_<is_convertible<_UElements,			     _Elements>...>::value>::type> constexpr tuple (_UElements
	   &&...__elements)
       constexpr tuple (const tuple &)=default
       constexpr tuple (tuple &&)=default
       template<typename... _UElements, typename  = typename enable_if<__and_<is_convertible<const
	   _UElements&, 		    _Elements>...>::value>::type> constexpr tuple (const tuple< _UElements...> &__in)
       template<typename... _UElements, typename  = typename
	   enable_if<__and_<is_convertible<_UElements,			     _Elements>...>::value>::type> constexpr tuple (tuple< _UElements...>
	   &&__in)
       template<typename _Alloc > tuple (allocator_arg_t __tag, const _Alloc &__a)
       template<typename _Alloc > tuple (allocator_arg_t __tag, const _Alloc &__a, const _Elements &...__elements)
       template<typename _Alloc , typename... _UElements, typename  = typename enable_if<sizeof...(_UElements)		   ==
	   sizeof...(_Elements)>::type> tuple (allocator_arg_t __tag, const _Alloc &__a, _UElements &&...__elements)
       template<typename _Alloc > tuple (allocator_arg_t __tag, const _Alloc &__a, const tuple &__in)
       template<typename _Alloc > tuple (allocator_arg_t __tag, const _Alloc &__a, tuple &&__in)
       template<typename _Alloc , typename... _UElements, typename  = typename enable_if<sizeof...(_UElements)		   ==
	   sizeof...(_Elements)>::type> tuple (allocator_arg_t __tag, const _Alloc &__a, const tuple< _UElements...> &__in)
       template<typename _Alloc , typename... _UElements, typename  = typename enable_if<sizeof...(_UElements)		   ==
	   sizeof...(_Elements)>::type> tuple (allocator_arg_t __tag, const _Alloc &__a, tuple< _UElements...> &&__in)
       void noexcept (noexcept(__in._M_swap(__in)))
       tuple & operator= (const tuple &__in)
       tuple & operator= (tuple &&__in) noexcept(is_nothrow_move_assignable< _Inherited >::value)
       template<typename... _UElements, typename  = typename enable_if<sizeof...(_UElements)		    == sizeof...(_Elements)>::type> tuple
	   & operator= (const tuple< _UElements...> &__in)
       template<typename... _UElements, typename  = typename enable_if<sizeof...(_UElements)		    == sizeof...(_Elements)>::type> tuple
	   & operator= (tuple< _UElements...> &&__in)

Detailed Description
   template<typename... _Elements>class std::tuple< _Elements >
       Primary class template, tuple.

       Definition at line 388 of file tuple.

Author
       Generated automatically by Doxygen for libstdc++ from the source code.

libstdc++							  Tue Jun 10 2014					std::tuple< _Elements >(3)
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