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SED: delete matching row and 4 next rows?
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SED: delete matching row and 4 next rows?
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03-19-2009
Shahul
Registered User
Join Date: Aug 2008
Location: India
Posts: 175
Hi,
Hope this also can help you..
Code:
sed
-n '/ProcessType:/ {n;n;n;n;n;p}' out1.lst
Thanks
Sha
Shahul
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