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SED: delete matching row and 4 next rows?
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SED: delete matching row and 4 next rows?
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03-19-2009
Franklin52
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Join Date: Feb 2007
Posts: 4,313
I misunderstood the question, this should delete the first 4 lines in all blocks:
Code:
nawk '/ProcessType:/{i=-4} i++ > 0' file
Regards
Franklin52
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