SED: delete matching row and 4 next rows? - Shell Programming and Scripting

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SED: delete matching row and 4 next rows?

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Thread: SED: delete matching row and 4 next rows?

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#3 (permalink)

03-19-2009

Juha

Registered User

Join Date: Sep 2006

Posts: 36

Thanks franklin, did not work for me however..

Code:

# awk '/ProcessType:/ && !p {i=-4;p=1} i++ > 0' file
awk: syntax error near line 1
awk: bailing out near line 1

With nawk it executes but only deletes the first occurrence of that "block"

Code:

# nawk '/ProcessType:/ && !p {i=-4;p=1} i++ > 0' file
ProcessType:    PROCESS_A (0)
SequenceNumber: 8286

2009 Mar 07  22:04:23:679   0:8286

ProcessType:    PROCESS_B (68)
SequenceNumber: 40689

2009 Mar 07  22:04:23:698  68:40689

DATA that should not be deleted

ProcessType:    PROCESS_B (68)
SequenceNumber: 40690
...