Hi.
I have the script shown below. If I execute it form the command line it seems to work properly, but when I fun it using the unix "at" command
"at -m now < ./kill-at-job.sh"
It appears to hang. Below is the script, the input file, and the execution as reported in the e-mail from the "at" processor. This is running on sunOS,
version 5.8.

Thanks !
Joe Simon

The script :

#!/bin/bash
#

set -x

# Get Info from :
# ~/builds/scripts/at-job.log
#
AT_LOG_FILE_NAME=~/builds/scripts/at-job.log

LINE_COUNT=0
while read LINE
do
# Need to skip first line, at job name is on 2nd line
if [[ $LINE_COUNT -eq 1 ]] ; then
set -- $LINE
AT_JOB="$2"
echo "AT Job ID = $AT_JOB"
break
fi
LINE_COUNT=$(($LINE_COUNT+1))
done < $AT_LOG_FILE_NAME

echo "Loop Complete"

The input file looks like this:

commands will be executed using /bin/bash
job 1237304740.a at Tue Mar 17 11:45:40 2009

The log file e-mailed to me looks like this:

Your "at" job on xxxx
"/var/spool/cron/atjobs/1237303896.a"

produced the following output:

+ AT_LOG_FILE_NAME=/xxx/builds/scripts/at-job.log
+ LINE_COUNT=0
+ read LINE
+ [[ 0 -eq 1 ]]
+ LINE_COUNT=1
+ read LINE
+ [[ 1 -eq 1 ]]
+ set -- job 1237304740.a at Tue Mar 17 11:45:40 2009
+ AT_JOB=1237304740.a
+ echo 'AT Job ID = 1237304740.a'
AT Job ID = 1237304740.a
+ break


If I remove the break (this is what I originally had), the execution looks like this:

+ AT_LOG_FILE_NAME=/export/home4/a10/simonj/builds/scripts/at-job.log
+ LINE_COUNT=0
+ read LINE
+ [[ 0 -eq 1 ]]
+ LINE_COUNT=1
+ read LINE
+ [[ 1 -eq 1 ]]
+ set -- job 1237304740.a at Tue Mar 17 11:45:40 2009
+ AT_JOB=1237304740.a
+ echo 'AT Job ID = 1237304740.a'
AT Job ID = 1237304740.a
+ LINE_COUNT=2
+ read LINE