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Full Discussion: unary operator expected
Top Forums Shell Programming and Scripting unary operator expected Post 302295072 by cfajohnson on Friday 6th of March 2009 01:56:41 PM
Old 03-06-2009
Quote:
Originally Posted by Satyak
i am trying to compare a value with value 50. but i am getting
"[: -lt: unary operator expected"

I am using

if [ $j -lt 50 ]
then
echo "------------"

fi

Make sure that $j expands to a value. Best is to set it explicitly, but you can also give it a default value (0 in this example):

Code:
if [ ${j:-0} -lt 50 ]

 

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DROP 
OPERATOR(7) SQL Commands DROP OPERATOR(7) NAME
DROP OPERATOR - remove an operator SYNOPSIS
DROP OPERATOR [ IF EXISTS ] name ( { lefttype | NONE } , { righttype | NONE } ) [ CASCADE | RESTRICT ] DESCRIPTION
DROP OPERATOR drops an existing operator from the database system. To execute this command you must be the owner of the operator. PARAMETERS
IF EXISTS Do not throw an error if the operator does not exist. A notice is issued in this case. name The name (optionally schema-qualified) of an existing operator. lefttype The data type of the operator's left operand; write NONE if the operator has no left operand. righttype The data type of the operator's right operand; write NONE if the operator has no right operand. CASCADE Automatically drop objects that depend on the operator. RESTRICT Refuse to drop the operator if any objects depend on it. This is the default. EXAMPLES
Remove the power operator a^b for type integer: DROP OPERATOR ^ (integer, integer); Remove the left unary bitwise complement operator ~b for type bit: DROP OPERATOR ~ (none, bit); Remove the right unary factorial operator x! for type bigint: DROP OPERATOR ! (bigint, none); COMPATIBILITY
There is no DROP OPERATOR statement in the SQL standard. SEE ALSO
CREATE OPERATOR [create_operator(7)], ALTER OPERATOR [alter_operator(7)] SQL - Language Statements 2010-05-14 DROP OPERATOR(7)
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