Hey

You can get the count of total arguments being passed. and then you can preserve all of'em except first 2 arguments using for loop.

echo 'num of args: '$#

following for loop will display all the arguments being passed:
for arg in "$@";
do
echo 'arg: '$arg;
done

You can run the while loop 2 less then the count of $#
var=`$# - 2`

you can then run the loop in reverse order, till value of var is achieved.

Hope you got what I am trying to convey.

Thanks
Varun Gupta