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Top Forums Shell Programming and Scripting Keeping padding in a date field Post 302275830 by cfajohnson on Monday 12th of January 2009 09:38:13 AM
Old 01-12-2009
Quote:
Originally Posted by seanbyrne
Still having a problem though, i'm plugging the variable into a sed command and its still not padding the %e variable:

Code:
CURRENT_DATE="$(date +"%a %b %e")"

sed -n '/^"$CURRENT_DATE"/,$ p' /var/sean/errorlog.log > /tmp/tempfile.tmp


You are not plugging the variable into the sed command; you are giving it a literal string because it is within single quotes.

Code:
CURRENT_DATE=$(date +"%a %b %e")
sed -n "/^$CURRENT_DATE/,$ p" /var/sean/errorlog.log > /tmp/tempfile.tmp

 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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