01-03-2009
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Shell programmer, author
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Join Date: Mar 2007
Location: Toronto, Canada
Posts: 2,361
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Quote:
Originally Posted by cjjoy
Hi,
My problem is, I can see the variable being set to 1 (success scenario) but once it comes outside the while loop the value is reset to 0.
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In all shells except ksh, all segments of a pipeline are executed in subshells.
Quote:
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Here is the my logCheck function, please let me know where I am wrong.
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Please put code inside [code] tags.
The standard syntax for defining a function is:
Code:
logCheck()
Quote:
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Code:
{
found=0; #sets to 1 if "success" is found
cat ${OUTPUT_LOG} |
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UUOC.
Quote:
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Code:
while read line
do
temp=`echo $line|grep "${SUCCESS_MESSAGE}"`
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UUOG.
Use a case statement rather than an external command:
Code:
case $line in
*"${SUCCESS_MESSAGE}"*) found=1
echo "string is found"
esac
Quote:
if [ $? -eq 0 ];then
found=1 <-- value is 1 here
echo "string is found"
echo "found value inside while is : $found"
fi
done
echo "found value outside while is $found" <-- found is 0 in all case
if [ $found = 1 ];then
return $SUCCESS;
else
return $FAILURE
fi
}
//output for success scenario:
string is found
found value inside while loop : 1
found value outside while loop is 0
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Last edited by cfajohnson; 01-04-2009 at 05:46 PM..
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