Hi all, im new to awk and would apreciate if you could tell me how to do this, i have a file with several entries like this:
Code:
2008-09-09 21:57:45 44 403 CUSTOM_EVENT Upgrade - end1
2008-09-09 21:57:46 45 403 CUSTOM_EVENT Component Check - start
2008-09-09 21:57:56 46 403 CUSTOM_EVENT Component Check - end
2008-09-09 21:57:56 47 403 CUSTOM_EVENT OSChecksum - start
2008-09-09 21:59:15 48 403 CUSTOM_EVENT OSChecksum - end
2008-09-09 21:59:15 49 403 CUSTOM_EVENT SELLogCheck - start
2008-09-09 22:01:39 50 403 CUSTOM_EVENT SELLogCheck - end
2008-09-09 22:01:40 51 403 CUSTOM_EVENT USB to Serial Connection Test - start
2008-09-09 22:43:46 52 403 CUSTOM_EVENT USB to Serial Connection Test - start
2008-09-09 22:44:15 53 403 CUSTOM_EVENT MemoryCheck - start
2008-09-09 22:44:16 54 403 CUSTOM_EVENT MemoryCheck - end
im trying to get the values on the last field, which would be the description of the event (eg. USB to Serial Connection Test - start) , but i need to further separate this field with a "-" to know if the test started or ended, the last field is a bit variable so i figured y could use something like this:
cat $1 | awk '{description = $6" "$7" "$8" "$9" "$10" "$11" "$12" "$13" "$14" "$15 ; print description }'
first i get all the fields from 6 to 15, and then, i tryed changing the FS to - and print the second field...
cat $1 | awk '{description = $6" "$7" "$8" "$9" "$10" "$11" "$12" "$13" "$14" "$15 ; FS="-" ; print description $2}'
of course, that prints the second field of the entire line, which is the year... hehe... is there a way to tell awk to output the variable's second field delimited by a "-"?
thanks all
