That was in lieu of this, dates are messy
Code:
echo $filename | \
sed 's/\(^[1-2][0-9]\{3\}\)-\([0-1][0-9]\)-\([0-3][0-9]\)-\([A-Z_0-9a-z]*\)/\4/' | read newfilename
if [[ ! -z newfilename ]] ; then
filename=$newfilename
fi
Basically I would suggest that naming every file with a leading date has problems. try
ls -l instead. Chris was technically correct -no doubt - but the usefulness of the above is limited. In part this is due to the way dates are constructed - and the above regex is not perfect. It will think 2008-19-19 is a date - which it is not. Most correct date regexes are several hundred character long. The only gold standard is to refer to the output of cal.
We use part of this date check algorithm below (simplified greatly) for validating old dates. This is more nearly complete && correct than most straight shell implementations using regex are likely to be. I deliberately excluded
Code:
/* chpdt.c
usage chpdt filename
echo "$filname" | chpdt
*/
#include <stdlib.h>
#include <string.h>
#include <limits.h>
#include <stdio.h>
#define isleapyr(y) (((y) % 4) == 0 && ((y) % 100) != 0 || ((y) % 400) == 0)
int leap[12]= {31,29,31,30,31,30,31,31,30,31,30,31};
int nleap[12]={31,28,31,30,31,30,31,31,30,31,30,31};
char *date_ok(char *result, char *src)
{
int value=atoi(src);
int month=0;
char *p=src;
int *v=nleap;
if( value >= 1900 && value < 2038 && (p=strchr(p, '-')) != NULL )
{
if(isleapyr(value))
v=leap;
value=atoi(++p);
if(value >= 1 && value < 13 && (p=strchr(p, '-')) != NULL)
{
month=value;
value=atoi(++p);
if( value > 0 && value < v[ month - 1 ] )
if( (p=strchr(p, '-')) != NULL)
result=++p;
}
}
return result;
}
char *name_ok(char *p, char *src)
{
if(src[4]=='-' && src[7]=='-' && src[10]=='-')
p=date_ok(p, src);
return p;
}
int main(int argc, char **argv)
{
int retval=0;
char tmp[PATH_MAX + 2]={0x0};
char *p=NULL;
if (argc < 2)
{
if(fgets(tmp, sizeof(tmp), stdin) ==NULL)
{
perror("I/O error");
retval=1;
};
p=strchr(tmp, '\n');
if(p!=NULL)
*p=0x0;
}
else
(void)strncpy(tmp, argv[1], PATH_MAX);
p=tmp;
if(strlen(tmp) > 10 && !retval) /* will return zero length if string is "date-"*/
p=name_ok(p, tmp);
if( fprintf(stdout, "%s", p) < 0)
{
perror("I/O error");
retval=1;
}
return retval;
}
Good luck with this.
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