What about this command?
Code:
find . -exec stat -c "%Y|%n" {} \; | sort -rn
which will give output like:
Code:
1226943267|./file73
1226943267|.
1226929499|./file70
1226929491|./file71
1226770385|./file63
1226770254|./file63.sav
1226677066|./file67
1226589199|./file68new
1226589041|./xab
1226589041|./xaa
If it is ok, then you can append a cut or awk to only print the filenames
The following version will show filetypes first.
Code:
find . -exec stat -c "%F|%Y|%n" {} \; | sort -rn
with output like
Code:
regular file|1226943267|./file73
regular file|1226929499|./file70
regular file|1226929491|./file71
regular file|1226770385|./file63
regular empty file|1226345695|./indic_file/ABCIND2008110901.TXT
regular empty file|1226345695|./indic_file/ABCIND2008110601.TXT
regular empty file|1225289894|./resnum/res4
directory|1226943267|.
directory|1225279229|./pass_var
directory|1225243924|./delete_extra
You could grep for "regular file", and then cut/awk to only include filenames.
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