who - uniq output - Shell Programming and Scripting

joeyg · #2 (**permalink**) 10-24-2008

The following works, but not sure if all necessary.

Code:

#! /usr/bin/bash

who | awk '{line[$1] = $1
     sum[$1]++}
    END{
     for(i in sum)
     if (sum[i]>0)
       print line[i]
}'

set array variable to the first read (which is name) field
increment a counter so I can know if anything in array value

step thru all values in my sum array
if the value in sum > 0 (meaning I have a match)
print out the corresponding entry in the line array