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Top Forums Shell Programming and Scripting Using unset to delete array elements Post 302250124 by fpmurphy on Wednesday 22nd of October 2008 06:13:06 PM
Old 10-22-2008
One way ....
Code:
$ test=(1 2 3 4)
$ echo ${test[@]}
1 2 3 4
$ test=( ${test[@]:0:1} ${test[@]:2:2})
$ echo ${test[@]}
1 3 4
$ echo ${test[1]}
3
$

 

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ARRAY_REPLACE(3)							 1							  ARRAY_REPLACE(3)

array_replace - Replaces elements from passed arrays into the first array

SYNOPSIS
array array_replace (array $array1, array $array2, [array $...]) DESCRIPTION
array_replace(3) replaces the values of $array1 with values having the same keys in each of the following arrays. If a key from the first array exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are passed for replacement, they will be processed in order, the later arrays overwriting the previous values. array_replace(3) is not recursive : it will replace values in the first array by whatever type is in the second array. PARAMETERS
o $array1 - The array in which elements are replaced. o $array2 - The array from which elements will be extracted. o $... - More arrays from which elements will be extracted. Values from later arrays overwrite the previous values. RETURN VALUES
Returns an array, or NULL if an error occurs. EXAMPLES
Example #1 array_replace(3) example <?php $base = array("orange", "banana", "apple", "raspberry"); $replacements = array(0 => "pineapple", 4 => "cherry"); $replacements2 = array(0 => "grape"); $basket = array_replace($base, $replacements, $replacements2); print_r($basket); ?> The above example will output: Array ( [0] => grape [1] => banana [2] => apple [3] => raspberry [4] => cherry ) SEE ALSO
array_replace_recursive(3), array_merge(3). PHP Documentation Group ARRAY_REPLACE(3)
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