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Top Forums Shell Programming and Scripting Redirecting part of output to stdout Post 302247376 by Legend986 on Wednesday 15th of October 2008 02:29:17 PM
Old 10-15-2008
Redirecting part of output to stdout

Hi,

I am trying to execute a command like this:

Code:
find ./ -name "*.gz" -exec sh -c 'zcat {} | awk -f parse.awk' \; >> output

If I want to print the filename, i generally use the -print argument to the find command but when I am redirecting the output to a file, how can I print just the filenames into stdout with the rest of the output into the file? Any help is much appreciated.

EDIT: Ah... Figured out... Sorry... Here's the solution:

Code:
find ./ -name "*.gz" -exec sh -c 'zcat {} | awk -f parse.awk >> output' \;

The solution was to put the redirection inside the exec itself...
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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