The UNIX and Linux Forums  
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.

Go Back   The UNIX and Linux Forums > Top Forums > Shell Programming and Scripting
.
google unix.com




View Single Post in the UNIX and Linux Forums - Click on the Thread or Permalink to View Entire Thread -->
  #3 (permalink)  
Old 09-18-2008
era era is offline Forum Advisor  
Herder of Useless Cats (On Sabbatical)
  
 

Join Date: Mar 2008
Location: /there/is/only/bin/sh
Posts: 3,652
Sorry, I posted my first reply based on a too cursory reading of your question.

Code:
sed '/:$/!b;N;/:\n$/d' input.txt
Here's a brief explanation:

/:$/!b - if not a line ending with a colon, just skip to the end of the script and print.
N - this is a line ending with a colon; fetch the next line and glue them together.
/:\n$/d - if the combined two lines match this pattern, delete
else, print

The \n thing works differently in different versions of sed, but if it doesn't work, try with a literal newline, with or without a backslash.

Last edited by era; 09-18-2008 at 05:56 AM.. Reason: Note on \n in different versions of sed