Sponsored Content
Top Forums Programming JAVA - External JAR files in UNIX Post 302222953 by vino on Friday 8th of August 2008 02:50:56 AM
Old 08-08-2008
Quote:
Originally Posted by satish2712
Hi,

I have to run my JAVA programs in UNIX server. The java program uses some external jar files for compiling. I have set the classpath to the folder where all the jar files are present using EXPORT classpath command.

But when i compile, it shows errors.. saying that the classes relating to the jar files are not found.

which means it is not recognising the jar files !!!

Please let me know how to make this compile ? Smilie
You should set CLASSPATH so that it points to the jar file. Pointing it to the folder will not work.
 

9 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

java.lang.System when running jar

Hello, I recieve the following error when trying to run the following command in a ksh. The operating system is AIX5.1. /usr/bin/jar -xvf {filename}.zip Can't find class java.lang.System But when I run it on the command line it unzips the file fine. Does anybody know why this... (2 Replies)
Discussion started by: ctcuser
2 Replies

2. UNIX for Dummies Questions & Answers

Accessing files on external USB drive using UNIX?

Hi Folks, I'm a serious UNIX newbie... I'm using a bash shell on Mac OS X. Basically I took up unix in order to use a specific image processing software package... I've learned enough to write a script to batch process all of my images, but I have so many that I would like to use an... (1 Reply)
Discussion started by: Slanter
1 Replies

3. UNIX for Dummies Questions & Answers

Possible to use a Java app with dll files on Unix-systems

Hi... I have build a program for the Velleman K8000 interface card, in java, which works just fine in windows, but now I want to use the program on a Unix-System. Is it possible to somehow convert the dll file to a format that Unix supports, or do I have to find another way? Dll-file:... (3 Replies)
Discussion started by: Scorp-D
3 Replies

4. Shell Programming and Scripting

Compiling all modified Java files in a folder on Unix

Hi all, I have a Unix script that will compile all Java files in a sub folder as follows: find . -name "*.java" -print -exec $JAVA_HOME/bin/javac -cp .:$CLASSPATH '{}' \; I would like to enhance it to only compile those Java files who: 1.) Have no class file 2.) Have a class file... (1 Reply)
Discussion started by: Annorax
1 Replies

5. Ubuntu

Add external Jar file

Hi, how to add external jar file in jsp application on eclipse. Thanks SN:confused: (0 Replies)
Discussion started by: snallusami
0 Replies

6. Shell Programming and Scripting

How to run the Shell Script from external directory using java?

Hi, I have created a Shell Script and invoke through java using Process Builder It's working fine, if (Shell script file ) in the same directory as java file. By Problem: How to run the Shell Script file( resides in external directory) using java. What configuration i have... (1 Reply)
Discussion started by: nanthagopal
1 Replies

7. Programming

Using basic UNIX commands to make/compile JAVA files

Hello! This is my first post, and I just learned what UNIX was this week. For a JAVA programming class I am taking, I must be able to create a directory in UNIX, use the nano command to create a JAVA program, compile it, and then run it on the command prompt using the java command. For some... (5 Replies)
Discussion started by: UNdvoItX
5 Replies

8. Shell Programming and Scripting

Executing java .jar from UNIX script

I have a .jar placed in my Unix directory. The .jar creates a .csv file .I want to execute the .jar and place the output file in a target Unix directory. The Unix Script is as follows. The issue that i am facing is that the file is not being placed in the REPORTDIR=/cdunix/IQNavigator/wrk instead... (4 Replies)
Discussion started by: pankajkargeti12
4 Replies

9. Shell Programming and Scripting

How to get CRC check sum of files in java EAR file without extracting .jar/.war files to disk.?

unzip -v gives CRC info of each file in a zip(in my case .EAR) file. # unzip -v my-application.ear Archive: my-application.ear Length Method Size Cmpr Date Time CRC-32 Name -------- ------ ------- ---- ---------- ----- -------- ---- 197981 Defl:N 183708 7%... (1 Reply)
Discussion started by: kchinnam
1 Replies
BND(1)							     BND for Debian GNU/Linux							    BND(1)

NAME
bnd - Create and diagnose OSGi R4 bundles. SYNOPSIS
bnd [general-options] [cmd] [cmd-options] bnd [general-options] <file>.jar bnd [general-options] <file>.bnd DESCRIPTION
The bnd tool helps you create and diagnose OSGi R4 bundles. The key functions are: * Show the manifest and JAR contents of a bundle * Wrap a JAR so that it becomes a bundle * Create a Bundle from a specification and a class path * Verify the validity of the manifest entries GENERAL OPTIONS
-failok Same as the property -failok. The current run will create a JAR file even if there were errors. -exceptions Will print the exception when the software has ran into a bad exception and bails out. Normally only a message is printed. For debugging or diagnostic reasons, the exception stack trace can be very helpful. COMMANDS
print ( -verify | -manifest | -list | - all ) * <file>.jar + The print function will take a list of JAR file and print one or more aspect of the JAF riles. The following aspects can be added. * -verify - Verify the JAR for consistency with the specification The print will exit with an error if the verify fails. * -manifest - Show the manifest * -list - List the entries in the JAR file * -all - Do all (this is the default. "bnd print -verify *.jar" buildx ( -classpath LIST | -eclipse <lt>file> | -noeclipse | -output <file> ) * <file>.bnd + The build function will assemble a bundle from the bnd specification. The default name of the output bundle is the name of the bnd file with a .jar extension. * -classpath - A list of JAR files and/or directories that should be placed on the class path before the calculation starts. * -eclipse - Parse the file as an Eclipse .classpath file, use the information to create an Eclipse's project class path. If this option is used, the default .classpath file is not read * -noeclipse - Do not parse the .classpath file of an Eclipse project. * -output - Override the default output name of the bundle or the directory. If the output is a directory, the name will be derived from the bnd file name. "bnd build -classpath bin -noeclipse -output test.jar xyz.bnd" wrap ( -classpath (<lt>file>(','<lt>file>)*)-output <lt>fileE|dir<gt> | -properties <lt>file> ) * -ignoremanifest? <lt>file>.jar * The wrap command takes an existing JAR file and guesses the manifest headers that will make this JAR useful for an OSGi Service Platform. If the output file is not overridden, the name of the input file is used with a .bar extension. The default bnd file for the header calculation is: Export-Package: * Import-Package: <packages inside the target jar> If the target bundle has a manifest, the headers are merged with the properties. The defaults can be overridden with a specific properties file. * -output - Set the output file or directory * -classpath - Sets the classpath as a comma separated list * -properties - Use a special property file for the manifest calculation. * -ignoremanifest - Do not include the manifest headers from the target bundle "bnd wrap -classpath osgi.jar *.jar" SEE ALSO
<http://www.aqute.biz/Code/Bnd> AUTHOR
Ludovic Claude <ludovic.claude@laposte.net> Damien Raude-Morvan <drazzib@debian.org> bnd-1.50.0 2011-10-25 BND(1)
All times are GMT -4. The time now is 08:44 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy