Friendz.. plz help me on this date function. - UNIX for Advanced & Expert Users

psn123 · #1 03-18-2008

Hi there.
Hi frndz,
I have to script a shell in such a way that by giving the current date, it should give the previous saturday date and next sunday date as output.
eg: Input - 01-01-2008
O/p -
last saturady- 30-12-2007(ddmmyy)
Next Sunday- 05-01-2008

Please help me in finding hw to do do it..plz.........

Yogesh Sawant · #2 03-18-2008

check if you can find a solution here

pchang · #3 07-18-2008

I'm also looking for a shell script that will return the previous Saturday's date from any given date.

Tried to look everywhere but cannot find any solution. I don't want to use the existing datecalc function.

Thank you.

shamrock · #4 07-18-2008

What platform are you on...because GNU's date utility can do this for you quite easily.

pchang · #5 07-18-2008

aix...

please provide example of GNU's date utility regardless and this might give me a clue.

Thank you.

fsahog · #6 07-18-2008

Please understand that I do not mean to distract from your desire for a script, but this is an excellent example, I think, of something which is bothersome with scripting but simple and straightforward with a C compiler. time(), localtime(), and the other date subroutines all give us excellent means to do this. perl or php also let you do fun things with dates. the UNIX "date" function kinda works with "now", unless of course you use the [-d|--date] option, but I don't see a simple way to make that work either. I had thought that if "date -d" would accept a julian date, then one could subtract a value related to the +%w value, but my CentOS 5 date program wouldn't take a julian date as input.

Sorry, I guess I just spoiled myself by writing C to do things like this. IMHO you might want to consider writing something in C, then using it as your date generator. If you are not comfortable with that, then perhaps perl or php might be helpful. Both are very powerful tools.

drl · #7 07-19-2008

Hi, pchang.

Quote:

Originally Posted by pchang

aix...

please provide example of GNU's date utility regardless and this might give me a clue.

Thank you.

Here are a few phrases date can understand and one that it cannot:

Code:

#!/bin/bash -

# @(#) s1       Demonstrate GNU date flexibility.

head -1 /etc/issue.net

echo
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version =o $(_eat $0 $1) date
set -o nounset
echo

echo " GNU date with English-like expressions:"
echo

date --date="2 weeks ago"
date --date="two weeks ago"

echo
date --date="today + 1 month"
date --date="3 years + 2 days"

exit 0

Producing:

Code:

$ ./s1
CentOS release 5 (Final)

(Versions displayed with local utility "version")
Linux 2.6.18-53.1.13.el5vm
GNU bash 3.1.17
date (GNU coreutils) 5.97

 GNU date with English-like expressions:

Sat Jul  5 15:55:46 CDT 2008
date: invalid date `two weeks ago'

Tue Aug 19 15:55:46 CDT 2008
Thu Jul 21 15:55:46 CDT 2011

As you can see, GNU date is extremely flexible.

I don't have access to an AIX box, but I suggest you look over man date to see if it has anything close ... cheers, drl

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