Originally Posted by joeyg

1) cat file | grep "^[0-9][0-9]" | wc -l
Or similar, if the normal file has numbers in the first couple character positions as user id or other identifier

2) cat file | cut -c1 | grep '"'
Assuming that the first field begins with a "

3) cat sample | tr "\n" " " | tr '"' "\n" | wc -l
Will produce a number. If normally three fields with " for each valid record, then take the resulting number from the command and divide by (twice the normal # fields).
The command above showed me 12 for my sample file, and I knew my sample has three fields with ". So 12/(3*2) = 2 records


p.s.
Be cautious of the "bump" to move a question. I always scan questions for those with zero responses - to work on first. Then, time permitting, go back to others that I previously skipped over. Therefore, your "bump" can have the reverse effect.